Base | Representation |
---|---|
bin | 11000011010101000… |
… | …10000101111010110 |
3 | 1020211112121111122111 |
4 | 30031110100233112 |
5 | 203321212122032 |
6 | 10004420421234 |
7 | 642556600024 |
oct | 141524205726 |
9 | 36745544574 |
10 | 13108317142 |
11 | 5617337758 |
12 | 2659b4781a |
13 | 130b96809b |
14 | 8c4cc3714 |
15 | 51abeac47 |
hex | 30d510bd6 |
13108317142 has 4 divisors (see below), whose sum is σ = 19662475716. Its totient is φ = 6554158570.
The previous prime is 13108317133. The next prime is 13108317161. The reversal of 13108317142 is 24171380131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277079284 + ... + 3277079287.
It is an arithmetic number, because the mean of its divisors is an integer number (4915618929).
Almost surely, 213108317142 is an apocalyptic number.
13108317142 is a deficient number, since it is larger than the sum of its proper divisors (6554158574).
13108317142 is an equidigital number, since it uses as much as digits as its factorization.
13108317142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6554158573.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 13108317142 its reverse (24171380131), we get a palindrome (37279697273).
It can be divided in two parts, 131083 and 17142, that added together give a square (148225 = 3852).
The spelling of 13108317142 in words is "thirteen billion, one hundred eight million, three hundred seventeen thousand, one hundred forty-two".
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