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131086514131 is a prime number
BaseRepresentation
bin111101000010101011…
…1010111011111010011
3110112100122101212210221
41322011113113133103
54121431121423011
6140115330533511
712320305662016
oct1720527273723
9415318355727
10131086514131
1150658a132a1
12214a4737297
13c4910130c1
1464b78d737d
153623433971
hex1e855d77d3

131086514131 has 2 divisors, whose sum is σ = 131086514132. Its totient is φ = 131086514130.

The previous prime is 131086514113. The next prime is 131086514147. The reversal of 131086514131 is 131415680131.

Together with previous prime (131086514113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131086514131 - 29 = 131086513619 is a prime.

It is a super-2 number, since 2×1310865141312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131086514431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65543257065 + 65543257066.

It is an arithmetic number, because the mean of its divisors is an integer number (65543257066).

Almost surely, 2131086514131 is an apocalyptic number.

131086514131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131086514131 is an equidigital number, since it uses as much as digits as its factorization.

131086514131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 34.

The spelling of 131086514131 in words is "one hundred thirty-one billion, eighty-six million, five hundred fourteen thousand, one hundred thirty-one".