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13110011041243 = 21416123312023
BaseRepresentation
bin1011111011000110100110…
…0011010001010111011011
31201102022020012200110101111
42332301221203101113123
53204243300311304433
643514353403001151
72522111203126144
oct276615143212733
951368205613344
1013110011041243
1141a4a195012a6
1215789842091b7
1374136554caac
14334756880acb
1517b04c710dcd
hexbec698d15db

13110011041243 has 4 divisors (see below), whose sum is σ = 13116134355408. Its totient is φ = 13103887727080.

The previous prime is 13110011041181. The next prime is 13110011041247. The reversal of 13110011041243 is 34214011001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110011041243 - 213 = 13110011033051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110011041247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3061653871 + ... + 3061658152.

It is an arithmetic number, because the mean of its divisors is an integer number (3279033588852).

Almost surely, 213110011041243 is an apocalyptic number.

13110011041243 is a deficient number, since it is larger than the sum of its proper divisors (6123314165).

13110011041243 is an equidigital number, since it uses as much as digits as its factorization.

13110011041243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6123314164.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 13110011041243 its reverse (34214011001131), we get a palindrome (47324022042374).

The spelling of 13110011041243 in words is "thirteen trillion, one hundred ten billion, eleven million, forty-one thousand, two hundred forty-three".

Divisors: 1 2141 6123312023 13110011041243