1311001310203 has 4 divisors (see below), whose sum is σ = 1411847564848. Its totient is φ = 1210155055560.

The previous prime is 1311001310197. The next prime is 1311001310207. The reversal of 1311001310203 is 3020131001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311001310203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311001310207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50423127303 + ... + 50423127328.

It is an arithmetic number, because the mean of its divisors is an integer number (352961891212).

Almost surely, 2^{1311001310203} is an apocalyptic number.

1311001310203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1311001310203 is a deficient number, since it is larger than the sum of its proper divisors (100846254645).

1311001310203 is a wasteful number, since it uses less digits than its factorization.

1311001310203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100846254644.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1311001310203 its reverse (3020131001131), we get a palindrome (4331132311334).

The spelling of 1311001310203 in words is "one trillion, three hundred eleven billion, one million, three hundred ten thousand, two hundred three".