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131100240402389 is a prime number
BaseRepresentation
bin11101110011110000100111…
…010000100101011111010101
3122012012001122011102202120202
4131303300213100211133111
5114140421243020334024
61142454341412110245
736420452112625556
oct3563604720453725
9565161564382522
10131100240402389
1138855332a27085
1212854131305385
13581c9130c249b
1424533dd56432d
1510253411d4bae
hex773c274257d5

131100240402389 has 2 divisors, whose sum is σ = 131100240402390. Its totient is φ = 131100240402388.

The previous prime is 131100240402289. The next prime is 131100240402401. The reversal of 131100240402389 is 983204042001131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96657074833489 + 34443165568900 = 9831433^2 + 5868830^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131100240402389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131100240402289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550120201194 + 65550120201195.

It is an arithmetic number, because the mean of its divisors is an integer number (65550120201195).

Almost surely, 2131100240402389 is an apocalyptic number.

It is an amenable number.

131100240402389 is a deficient number, since it is larger than the sum of its proper divisors (1).

131100240402389 is an equidigital number, since it uses as much as digits as its factorization.

131100240402389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 131100240402389 in words is "one hundred thirty-one trillion, one hundred billion, two hundred forty million, four hundred two thousand, three hundred eighty-nine".