13110033014341 has 4 divisors (see below), whose sum is σ = 13196854425184. Its totient is φ = 13023211603500.

The previous prime is 13110033014321. The next prime is 13110033014399. The reversal of 13110033014341 is 14341033001131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110033014341 - 2²¹ = 13110030917189 is a prime.

It is a super-2 number, since 2×13110033014341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110033014321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43410705195 + ... + 43410705496.

It is an arithmetic number, because the mean of its divisors is an integer number (3299213606296).

Almost surely, 2^{13110033014341} is an apocalyptic number.

It is an amenable number.

13110033014341 is a deficient number, since it is larger than the sum of its proper divisors (86821410843).

13110033014341 is an equidigital number, since it uses as much as digits as its factorization.

13110033014341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86821410842.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13110033014341 its reverse (14341033001131), we get a palindrome (27451066015472).

The spelling of 13110033014341 in words is "thirteen trillion, one hundred ten billion, thirty-three million, fourteen thousand, three hundred forty-one".