Base | Representation |
---|---|
bin | 10011000100111101111… |
… | …000110010101010001001 |
3 | 11122022221002001011210021 |
4 | 103010331320302222021 |
5 | 132434413322314032 |
6 | 2442133331020441 |
7 | 163500612244333 |
oct | 23047570625211 |
9 | 4568832034707 |
10 | 1311003323017 |
11 | 465aa221a683 |
12 | 1920b843a721 |
13 | 9681c91646b |
14 | 4764aa82453 |
15 | 2417ee1e097 |
hex | 1313de32a89 |
1311003323017 has 4 divisors (see below), whose sum is σ = 1368003467520. Its totient is φ = 1254003178516.
The previous prime is 1311003323011. The next prime is 1311003323053. The reversal of 1311003323017 is 7103233001131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1311003323017 - 235 = 1276643584649 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1311003322982 and 1311003323000.
It is not an unprimeable number, because it can be changed into a prime (1311003323011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28500072217 + ... + 28500072262.
It is an arithmetic number, because the mean of its divisors is an integer number (342000866880).
Almost surely, 21311003323017 is an apocalyptic number.
It is an amenable number.
1311003323017 is a deficient number, since it is larger than the sum of its proper divisors (57000144503).
1311003323017 is an equidigital number, since it uses as much as digits as its factorization.
1311003323017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57000144502.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1311003323017 its reverse (7103233001131), we get a palindrome (8414236324148).
The spelling of 1311003323017 in words is "one trillion, three hundred eleven billion, three million, three hundred twenty-three thousand, seventeen".
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