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13110034541413 is a prime number
BaseRepresentation
bin1011111011000110101011…
…1100111010101101100101
31201102022021211220101120011
42332301222330322231211
53204243322320311123
643514400002410221
72522111606643565
oct276615274725545
951368254811504
1013110034541413
1141a4a307a2327
121578990060971
1374136a38a414
14334759a3ada5
1517b04e803e0d
hexbec6af3ab65

13110034541413 has 2 divisors, whose sum is σ = 13110034541414. Its totient is φ = 13110034541412.

The previous prime is 13110034541389. The next prime is 13110034541441. The reversal of 13110034541413 is 31414543001131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9046818730849 + 4063215810564 = 3007793^2 + 2015742^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110034541413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110034541113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555017270706 + 6555017270707.

It is an arithmetic number, because the mean of its divisors is an integer number (6555017270707).

Almost surely, 213110034541413 is an apocalyptic number.

It is an amenable number.

13110034541413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110034541413 is an equidigital number, since it uses as much as digits as its factorization.

13110034541413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13110034541413 its reverse (31414543001131), we get a palindrome (44524577542544).

The spelling of 13110034541413 in words is "thirteen trillion, one hundred ten billion, thirty-four million, five hundred forty-one thousand, four hundred thirteen".