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13110101020222 = 26555050510111
BaseRepresentation
bin1011111011000110111011…
…1010100000111000111110
31201102022110110222212100021
42332301232322200320332
53204243441330121342
643514410335322354
72522113345003423
oct276615672407076
951368413885307
1013110101020222
1141a4a65278898
1215789aa3803ba
1374137b0952ab
143347647c3d4a
1517b055586567
hexbec6eea0e3e

13110101020222 has 4 divisors (see below), whose sum is σ = 19665151530336. Its totient is φ = 6555050510110.

The previous prime is 13110101020193. The next prime is 13110101020327. The reversal of 13110101020222 is 22202010101131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13110101020196 and 13110101020205.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277525255054 + ... + 3277525255057.

It is an arithmetic number, because the mean of its divisors is an integer number (4916287882584).

Almost surely, 213110101020222 is an apocalyptic number.

13110101020222 is a deficient number, since it is larger than the sum of its proper divisors (6555050510114).

13110101020222 is an equidigital number, since it uses as much as digits as its factorization.

13110101020222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6555050510113.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13110101020222 its reverse (22202010101131), we get a palindrome (35312111121353).

The spelling of 13110101020222 in words is "thirteen trillion, one hundred ten billion, one hundred one million, twenty thousand, two hundred twenty-two".

Divisors: 1 2 6555050510111 13110101020222