Base | Representation |
---|---|
bin | 10011000100111110010… |
… | …011011101001110011001 |
3 | 11122022221120012022101201 |
4 | 103010332103131032121 |
5 | 132434422120004423 |
6 | 2442134140514201 |
7 | 163501025536534 |
oct | 23047623351631 |
9 | 4568846168351 |
10 | 1311010313113 |
11 | 465aa6164416 |
12 | 1920ba84b961 |
13 | 968211c3007 |
14 | 4764b981a1b |
15 | 241808502ad |
hex | 1313e4dd399 |
1311010313113 has 2 divisors, whose sum is σ = 1311010313114. Its totient is φ = 1311010313112.
The previous prime is 1311010313111. The next prime is 1311010313117. The reversal of 1311010313113 is 3113130101131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1113778397449 + 197231915664 = 1055357^2 + 444108^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311010313113 - 21 = 1311010313111 is a prime.
Together with 1311010313111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1311010313111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655505156556 + 655505156557.
It is an arithmetic number, because the mean of its divisors is an integer number (655505156557).
Almost surely, 21311010313113 is an apocalyptic number.
It is an amenable number.
1311010313113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311010313113 is an equidigital number, since it uses as much as digits as its factorization.
1311010313113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 1311010313113 its reverse (3113130101131), we get a palindrome (4424140414244).
The spelling of 1311010313113 in words is "one trillion, three hundred eleven billion, ten million, three hundred thirteen thousand, one hundred thirteen".
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