131101102121 has 4 divisors (see below), whose sum is σ = 143019384144. Its totient is φ = 119182820100.

The previous prime is 131101102117. The next prime is 131101102193. The reversal of 131101102121 is 121201101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131101102121 - 2² = 131101102117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131101102096 and 131101102105.

It is not an unprimeable number, because it can be changed into a prime (131101108121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5959140995 + ... + 5959141016.

It is an arithmetic number, because the mean of its divisors is an integer number (35754846036).

Almost surely, 2^131101102121 is an apocalyptic number.

131101102121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131101102121 is a deficient number, since it is larger than the sum of its proper divisors (11918282023).

131101102121 is a wasteful number, since it uses less digits than its factorization.

131101102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11918282022.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 131101102121 its reverse (121201101131), we get a palindrome (252302203252).

The spelling of 131101102121 in words is "one hundred thirty-one billion, one hundred one million, one hundred two thousand, one hundred twenty-one".