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13110110420203 is a prime number
BaseRepresentation
bin1011111011000110111101…
…1110010111110011101011
31201102022111010200102200201
42332301233132113303223
53204244001231421303
643514411313013031
72522113520623546
oct276615736276353
951368433612621
1013110110420203
1141a4a6a609175
1215789b1554177
13741380006a04
14334765b4d85d
1517b0562e181d
hexbec6f797ceb

13110110420203 has 2 divisors, whose sum is σ = 13110110420204. Its totient is φ = 13110110420202.

The previous prime is 13110110420201. The next prime is 13110110420221. The reversal of 13110110420203 is 30202401101131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110110420203 - 21 = 13110110420201 is a prime.

It is a super-2 number, since 2×131101104202032 (a number of 27 digits) contains 22 as substring.

Together with 13110110420201, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13110110420201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555055210101 + 6555055210102.

It is an arithmetic number, because the mean of its divisors is an integer number (6555055210102).

Almost surely, 213110110420203 is an apocalyptic number.

13110110420203 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110110420203 is an equidigital number, since it uses as much as digits as its factorization.

13110110420203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13110110420203 its reverse (30202401101131), we get a palindrome (43312511521334).

The spelling of 13110110420203 in words is "thirteen trillion, one hundred ten billion, one hundred ten million, four hundred twenty thousand, two hundred three".