Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0001110001010110001011 |
3 | 1201102022111012100200222012 |
4 | 2332301233201301112023 |
5 | 3204244001443424433 |
6 | 43514411344050135 |
7 | 2522113531324412 |
oct | 276615741612613 |
9 | 51368435320865 |
10 | 13110111311243 |
11 | 41a4a70067671 |
12 | 15789b190394b |
13 | 74138025945b |
14 | 334765d02479 |
15 | 17b05641a848 |
hex | bec6f87158b |
13110111311243 has 4 divisors (see below), whose sum is σ = 13110275948160. Its totient is φ = 13109946674328.
The previous prime is 13110111311201. The next prime is 13110111311249. The reversal of 13110111311243 is 34211311101131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13110111311243 - 26 = 13110111311179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110111311249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82198955 + ... + 82358292.
It is an arithmetic number, because the mean of its divisors is an integer number (3277568987040).
Almost surely, 213110111311243 is an apocalyptic number.
13110111311243 is a deficient number, since it is larger than the sum of its proper divisors (164636917).
13110111311243 is an equidigital number, since it uses as much as digits as its factorization.
13110111311243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164636916.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 13110111311243 its reverse (34211311101131), we get a palindrome (47321422412374).
The spelling of 13110111311243 in words is "thirteen trillion, one hundred ten billion, one hundred eleven million, three hundred eleven thousand, two hundred forty-three".
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