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13110112017973 is a prime number
BaseRepresentation
bin1011111011000110111110…
…0100011101111000110101
31201102022111020200121102101
42332301233210131320311
53204244002134033343
643514411411142101
72522113540330015
oct276615744357065
951368436617371
1013110112017973
1141a4a704aa643
1215789b1ba4931
13741380446039
14334766047c45
1517b056509e4d
hexbec6f91de35

13110112017973 has 2 divisors, whose sum is σ = 13110112017974. Its totient is φ = 13110112017972.

The previous prime is 13110112017941. The next prime is 13110112017979. The reversal of 13110112017973 is 37971021101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12749634259569 + 360477758404 = 3570663^2 + 600398^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110112017973 - 25 = 13110112017941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110112017979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056008986 + 6555056008987.

It is an arithmetic number, because the mean of its divisors is an integer number (6555056008987).

Almost surely, 213110112017973 is an apocalyptic number.

It is an amenable number.

13110112017973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110112017973 is an equidigital number, since it uses as much as digits as its factorization.

13110112017973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7938, while the sum is 37.

The spelling of 13110112017973 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, seventeen thousand, nine hundred seventy-three".