Base | Representation |
---|---|
bin | 11000011010110110… |
… | …01001001011110010 |
3 | 1020211200000011100112 |
4 | 30031123021023302 |
5 | 203322142334302 |
6 | 10004523221322 |
7 | 642611122463 |
oct | 141533111362 |
9 | 36750004315 |
10 | 13110121202 |
11 | 561835a112 |
12 | 265a677842 |
13 | 130c14a289 |
14 | 8c5232d6a |
15 | 51ae55552 |
hex | 30d6c92f2 |
13110121202 has 4 divisors (see below), whose sum is σ = 19665181806. Its totient is φ = 6555060600.
The previous prime is 13110121153. The next prime is 13110121207. The reversal of 13110121202 is 20212101131.
13110121202 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7946117881 + 5164003321 = 89141^2 + 71861^2 .
It is a super-4 number, since 4×131101212024 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (13110121207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277530299 + ... + 3277530302.
Almost surely, 213110121202 is an apocalyptic number.
13110121202 is a deficient number, since it is larger than the sum of its proper divisors (6555060604).
13110121202 is an equidigital number, since it uses as much as digits as its factorization.
13110121202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6555060603.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 13110121202 its reverse (20212101131), we get a palindrome (33322222333).
The spelling of 13110121202 in words is "thirteen billion, one hundred ten million, one hundred twenty-one thousand, two hundred two".
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