131101230055541 has 2 divisors, whose sum is σ = 131101230055542. Its totient is φ = 131101230055540.

The previous prime is 131101230055441. The next prime is 131101230055553. The reversal of 131101230055541 is 145550032101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102198553048900 + 28902677006641 = 10109330^2 + 5376121^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101230055541 - 2²² = 131101225861237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131101230055498 and 131101230055507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101230055591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550615027770 + 65550615027771.

It is an arithmetic number, because the mean of its divisors is an integer number (65550615027771).

Almost surely, 2^{131101230055541} is an apocalyptic number.

It is an amenable number.

131101230055541 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101230055541 is an equidigital number, since it uses as much as digits as its factorization.

131101230055541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 131101230055541 its reverse (145550032101131), we get a palindrome (276651262156672).

The spelling of 131101230055541 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, fifty-five thousand, five hundred forty-one".