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131101230100453 is a prime number
BaseRepresentation
bin11101110011110001100010…
…001111111110111111100101
3122012012011012010201122002121
4131303301202033332333211
5114140430304401203303
61142455023524505541
736420515461131634
oct3563614217767745
9565164163648077
10131101230100453
11388557a0653968
121285436884b2b1
13581ca40163542
142453494b8d51b
15102539d02d9bd
hex773c623fefe5

131101230100453 has 2 divisors, whose sum is σ = 131101230100454. Its totient is φ = 131101230100452.

The previous prime is 131101230100439. The next prime is 131101230100531. The reversal of 131101230100453 is 354001032101131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120982004669124 + 10119225431329 = 10999182^2 + 3181073^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101230100453 - 221 = 131101228003301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101630100453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550615050226 + 65550615050227.

It is an arithmetic number, because the mean of its divisors is an integer number (65550615050227).

Almost surely, 2131101230100453 is an apocalyptic number.

It is an amenable number.

131101230100453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101230100453 is an equidigital number, since it uses as much as digits as its factorization.

131101230100453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 131101230100453 its reverse (354001032101131), we get a palindrome (485102262201584).

The spelling of 131101230100453 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, one hundred thousand, four hundred fifty-three".