Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …011000111010100100111 |
3 | 11122022221200222022002021 |
4 | 103010332123013110213 |
5 | 132434423123224201 |
6 | 2442134251524011 |
7 | 163501051600243 |
oct | 23047633072447 |
9 | 4568850868067 |
10 | 1311012320551 |
11 | 465aa730565a |
12 | 1920bb459607 |
13 | 9682174694b |
14 | 4764bd45423 |
15 | 24180ae9ea1 |
hex | 1313e6c7527 |
1311012320551 has 2 divisors, whose sum is σ = 1311012320552. Its totient is φ = 1311012320550.
The previous prime is 1311012320483. The next prime is 1311012320581. The reversal of 1311012320551 is 1550232101131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311012320551 - 229 = 1310475449639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311012320581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655506160275 + 655506160276.
It is an arithmetic number, because the mean of its divisors is an integer number (655506160276).
Almost surely, 21311012320551 is an apocalyptic number.
1311012320551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311012320551 is an equidigital number, since it uses as much as digits as its factorization.
1311012320551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 1311012320551 its reverse (1550232101131), we get a palindrome (2861244421682).
The spelling of 1311012320551 in words is "one trillion, three hundred eleven billion, twelve million, three hundred twenty thousand, five hundred fifty-one".
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