13110123320033 has 2 divisors, whose sum is σ = 13110123320034. Its totient is φ = 13110123320032.

The previous prime is 13110123320009. The next prime is 13110123320039. The reversal of 13110123320033 is 33002332101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13107238233664 + 2885086369 = 3620392^2 + 53713^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110123320033 - 2¹⁴ = 13110123303649 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110123319990 and 13110123320008.

It is not a weakly prime, because it can be changed into another prime (13110123320039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555061660016 + 6555061660017.

It is an arithmetic number, because the mean of its divisors is an integer number (6555061660017).

Almost surely, 2^{13110123320033} is an apocalyptic number.

It is an amenable number.

13110123320033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110123320033 is an equidigital number, since it uses as much as digits as its factorization.

13110123320033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13110123320033 its reverse (33002332101131), we get a palindrome (46112455421164).

The spelling of 13110123320033 in words is "thirteen trillion, one hundred ten billion, one hundred twenty-three million, three hundred twenty thousand, thirty-three".