Base | Representation |
---|---|
bin | 1011111011000111000011… |
… | …0101011001010110000111 |
3 | 1201102022112201121110000021 |
4 | 2332301300311121112013 |
5 | 3204244023101424111 |
6 | 43514413450000011 |
7 | 2522114215546342 |
oct | 276616065312607 |
9 | 51368481543007 |
10 | 13110133233031 |
11 | 41a4a8147a84a |
12 | 15789b9116007 |
13 | 741384963523 |
14 | 334768bab459 |
15 | 17b0582ead71 |
hex | bec70d59587 |
13110133233031 has 2 divisors, whose sum is σ = 13110133233032. Its totient is φ = 13110133233030.
The previous prime is 13110133233019. The next prime is 13110133233047. The reversal of 13110133233031 is 13033233101131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13110133233031 - 233 = 13101543298439 is a prime.
It is a super-2 number, since 2×131101332330312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13110133232987 and 13110133233005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110133234031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555066616515 + 6555066616516.
It is an arithmetic number, because the mean of its divisors is an integer number (6555066616516).
Almost surely, 213110133233031 is an apocalyptic number.
13110133233031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110133233031 is an equidigital number, since it uses as much as digits as its factorization.
13110133233031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13110133233031 its reverse (13033233101131), we get a palindrome (26143366334162).
The spelling of 13110133233031 in words is "thirteen trillion, one hundred ten billion, one hundred thirty-three million, two hundred thirty-three thousand, thirty-one".
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