131101334525134 has 4 divisors (see below), whose sum is σ = 196652001787704. Its totient is φ = 65550667262566.

The previous prime is 131101334525129. The next prime is 131101334525177. The reversal of 131101334525134 is 431525433101131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×131101334525134³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131101334525093 and 131101334525102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32775333631282 + ... + 32775333631285.

It is an arithmetic number, because the mean of its divisors is an integer number (49163000446926).

Almost surely, 2^{131101334525134} is an apocalyptic number.

131101334525134 is a deficient number, since it is larger than the sum of its proper divisors (65550667262570).

131101334525134 is an equidigital number, since it uses as much as digits as its factorization.

131101334525134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65550667262569.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 131101334525134 its reverse (431525433101131), we get a palindrome (562626767626265).

The spelling of 131101334525134 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred thirty-four million, five hundred twenty-five thousand, one hundred thirty-four".