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13110202321 = 59222206819
BaseRepresentation
bin11000011010110110…
…11100111111010001
31020211200011021121221
430031123130333101
5203322202433241
610004525045041
7642611611126
oct141533347721
936750137557
1013110202321
115618405057
12265a6b6781
13130c178188
148c525474d
1551ae6e5d1
hex30d6dcfd1

13110202321 has 4 divisors (see below), whose sum is σ = 13332409200. Its totient is φ = 12887995444.

The previous prime is 13110202319. The next prime is 13110202333. The reversal of 13110202321 is 12320201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110202321 - 21 = 13110202319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110202295 and 13110202304.

It is not an unprimeable number, because it can be changed into a prime (13110202351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111103351 + ... + 111103468.

It is an arithmetic number, because the mean of its divisors is an integer number (3333102300).

Almost surely, 213110202321 is an apocalyptic number.

It is an amenable number.

13110202321 is a deficient number, since it is larger than the sum of its proper divisors (222206879).

13110202321 is an equidigital number, since it uses as much as digits as its factorization.

13110202321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222206878.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13110202321 its reverse (12320201131), we get a palindrome (25430403452).

The spelling of 13110202321 in words is "thirteen billion, one hundred ten million, two hundred two thousand, three hundred twenty-one".

Divisors: 1 59 222206819 13110202321