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1311021414193 is a prime number
BaseRepresentation
bin10011000100111110111…
…101110011011100110001
311122022222100002022012211
4103010332331303130301
5132434432440223233
62442135214452121
7163501222103311
oct23047675633461
94568870068184
101311021414193
11466001456867
12192102504041
13968235ababa
144764d231441
15241817e45cd
hex1313ef73731

1311021414193 has 2 divisors, whose sum is σ = 1311021414194. Its totient is φ = 1311021414192.

The previous prime is 1311021414181. The next prime is 1311021414233. The reversal of 1311021414193 is 3914141201131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1295244295744 + 15777118449 = 1138088^2 + 125607^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311021414193 is a prime.

It is a super-4 number, since 4×13110214141934 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1311021414293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655510707096 + 655510707097.

It is an arithmetic number, because the mean of its divisors is an integer number (655510707097).

Almost surely, 21311021414193 is an apocalyptic number.

It is an amenable number.

1311021414193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311021414193 is an equidigital number, since it uses as much as digits as its factorization.

1311021414193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 1311021414193 in words is "one trillion, three hundred eleven billion, twenty-one million, four hundred fourteen thousand, one hundred ninety-three".