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1311021414233 is a prime number
BaseRepresentation
bin10011000100111110111…
…101110011011101011001
311122022222100002022021022
4103010332331303131121
5132434432440223413
62442135214452225
7163501222103366
oct23047675633531
94568870068238
101311021414233
114660014568a3
12192102504075
13968235abb1b
144764d23146d
15241817e4608
hex1313ef73759

1311021414233 has 2 divisors, whose sum is σ = 1311021414234. Its totient is φ = 1311021414232.

The previous prime is 1311021414193. The next prime is 1311021414239. The reversal of 1311021414233 is 3324141201131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 795435664384 + 515585749849 = 891872^2 + 718043^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311021414233 - 26 = 1311021414169 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311021414239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655510707116 + 655510707117.

It is an arithmetic number, because the mean of its divisors is an integer number (655510707117).

Almost surely, 21311021414233 is an apocalyptic number.

It is an amenable number.

1311021414233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311021414233 is an equidigital number, since it uses as much as digits as its factorization.

1311021414233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1311021414233 its reverse (3324141201131), we get a palindrome (4635162615364).

The spelling of 1311021414233 in words is "one trillion, three hundred eleven billion, twenty-one million, four hundred fourteen thousand, two hundred thirty-three".