1311022113132 has 12 divisors (see below), whose sum is σ = 3059051597336. Its totient is φ = 437007371040.

The previous prime is 1311022113101. The next prime is 1311022113133. The reversal of 1311022113132 is 2313112201131.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-4 number, since 4×1311022113132⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1311022113099 and 1311022113108.

It is not an unprimeable number, because it can be changed into a prime (1311022113133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54625921369 + ... + 54625921392.

Almost surely, 2^{1311022113132} is an apocalyptic number.

1311022113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1311022113132 is an abundant number, since it is smaller than the sum of its proper divisors (1748029484204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311022113132 is a wasteful number, since it uses less digits than its factorization.

1311022113132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109251842768 (or 109251842766 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1311022113132 its reverse (2313112201131), we get a palindrome (3624134314263).

The spelling of 1311022113132 in words is "one trillion, three hundred eleven billion, twenty-two million, one hundred thirteen thousand, one hundred thirty-two".