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13110222133 = 42019312007
BaseRepresentation
bin11000011010110111…
…00001110100110101
31020211200012021210201
430031123201310311
5203322204102013
610004525320501
7642612022651
oct141533416465
936750167721
1013110222133
115618418a28
12265a706131
13130c1841b8
148c525ba61
1551ae753dd
hex30d6e1d35

13110222133 has 4 divisors (see below), whose sum is σ = 13110576160. Its totient is φ = 13109868108.

The previous prime is 13110222131. The next prime is 13110222143. The reversal of 13110222133 is 33122201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110222133 - 21 = 13110222131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13110222133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110222131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113985 + ... + 198022.

It is an arithmetic number, because the mean of its divisors is an integer number (3277644040).

Almost surely, 213110222133 is an apocalyptic number.

It is an amenable number.

13110222133 is a deficient number, since it is larger than the sum of its proper divisors (354027).

13110222133 is an equidigital number, since it uses as much as digits as its factorization.

13110222133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354026.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13110222133 its reverse (33122201131), we get a palindrome (46232423264).

The spelling of 13110222133 in words is "thirteen billion, one hundred ten million, two hundred twenty-two thousand, one hundred thirty-three".

Divisors: 1 42019 312007 13110222133