13110241402 has 4 divisors (see below), whose sum is σ = 19665362106. Its totient is φ = 6555120700.

The previous prime is 13110241301. The next prime is 13110241409. The reversal of 13110241402 is 20414201131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20414201131 = 59 ⋅346003409.

It can be written as a sum of positive squares in only one way, i.e., 7307001361 + 5803240041 = 85481^2 + 76179^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13110241402.

It is not an unprimeable number, because it can be changed into a prime (13110241409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277560349 + ... + 3277560352.

Almost surely, 2^13110241402 is an apocalyptic number.

13110241402 is a deficient number, since it is larger than the sum of its proper divisors (6555120704).

13110241402 is an equidigital number, since it uses as much as digits as its factorization.

13110241402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6555120703.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13110241402 its reverse (20414201131), we get a palindrome (33524442533).

The spelling of 13110241402 in words is "thirteen billion, one hundred ten million, two hundred forty-one thousand, four hundred two".