13110241301 has 2 divisors, whose sum is σ = 13110241302. Its totient is φ = 13110241300.

The previous prime is 13110241267. The next prime is 13110241409. The reversal of 13110241301 is 10314201131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12757928401 + 352312900 = 112951^2 + 18770^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110241301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13110241301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110241601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555120650 + 6555120651.

It is an arithmetic number, because the mean of its divisors is an integer number (6555120651).

Almost surely, 2^13110241301 is an apocalyptic number.

It is an amenable number.

13110241301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110241301 is an equidigital number, since it uses as much as digits as its factorization.

13110241301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110241301 its reverse (10314201131), we get a palindrome (23424442432).

The spelling of 13110241301 in words is "thirteen billion, one hundred ten million, two hundred forty-one thousand, three hundred one".