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13110300300203 = 79306479541483
BaseRepresentation
bin1011111011000111101011…
…0010101101001110101011
31201102022222100222100002022
42332301322302231032223
53204244343334101303
643514442214455055
72522121314601551
oct276617262551653
951368870870068
1013110300300203
1141a5057809897
121578a4506448b
137413b0459942
14334783059bd1
1517b067cec438
hexbec7acad3ab

13110300300203 has 8 divisors (see below), whose sum is σ = 13276321305600. Its totient is φ = 12944280990888.

The previous prime is 13110300300197. The next prime is 13110300300211. The reversal of 13110300300203 is 30200300301131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110300300203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110300300233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23941100 + ... + 24482582.

It is an arithmetic number, because the mean of its divisors is an integer number (1659540163200).

Almost surely, 213110300300203 is an apocalyptic number.

13110300300203 is a deficient number, since it is larger than the sum of its proper divisors (166021005397).

13110300300203 is an equidigital number, since it uses as much as digits as its factorization.

13110300300203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 848041.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13110300300203 its reverse (30200300301131), we get a palindrome (43310600601334).

The spelling of 13110300300203 in words is "thirteen trillion, one hundred ten billion, three hundred million, three hundred thousand, two hundred three".

Divisors: 1 79 306479 541483 24211841 42777157 165953168357 13110300300203