13110301201122 has 12 divisors (see below), whose sum is σ = 28405652602470. Its totient is φ = 4370100400368.

The previous prime is 13110301201121. The next prime is 13110301201157. The reversal of 13110301201122 is 22110210301131.

13110301201122 is a `hidden beast` number, since 1 + 31 + 10 + 301 + 201 + 122 = 666.

It can be written as a sum of positive squares in only one way, i.e., 11691126954441 + 1419174246681 = 3419229^2 + 1191291^2 .

It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 728350066729 = 13110301201122 / (1 + 3 + 1 + 1 + 0 + 3 + 0 + 1 + 2 + 0 + 1 + 1 + 2 + 2).

It is a junction number, because it is equal to n+sod(n) for n = 13110301201095 and 13110301201104.

It is not an unprimeable number, because it can be changed into a prime (13110301201121) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 364175033347 + ... + 364175033382.

Almost surely, 2^{13110301201122} is an apocalyptic number.

13110301201122 is an abundant number, since it is smaller than the sum of its proper divisors (15295351401348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110301201122 is a wasteful number, since it uses less digits than its factorization.

13110301201122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 728350066737 (or 728350066734 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13110301201122 its reverse (22110210301131), we get a palindrome (35220511502253).

It can be divided in two parts, 1311030 and 1201122, that added together give a palindrome (2512152).

The spelling of 13110301201122 in words is "thirteen trillion, one hundred ten billion, three hundred one million, two hundred one thousand, one hundred twenty-two".