13110303113 has 2 divisors, whose sum is σ = 13110303114. Its totient is φ = 13110303112.

The previous prime is 13110303109. The next prime is 13110303133. The reversal of 13110303113 is 31130301131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6631984969 + 6478318144 = 81437^2 + 80488^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110303113 - 2² = 13110303109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110303091 and 13110303100.

It is not a weakly prime, because it can be changed into another prime (13110303133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555151556 + 6555151557.

It is an arithmetic number, because the mean of its divisors is an integer number (6555151557).

Almost surely, 2^13110303113 is an apocalyptic number.

It is an amenable number.

13110303113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110303113 is an equidigital number, since it uses as much as digits as its factorization.

13110303113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13110303113 its reverse (31130301131), we get a palindrome (44240604244).

The spelling of 13110303113 in words is "thirteen billion, one hundred ten million, three hundred three thousand, one hundred thirteen".