Base | Representation |
---|---|
bin | 1011111011000111101101… |
… | …1111011101100001010101 |
3 | 1201102100000012001101112221 |
4 | 2332301323133131201111 |
5 | 3204244404340013331 |
6 | 43514443314142341 |
7 | 2522121516404206 |
oct | 276617337354125 |
9 | 51370005041487 |
10 | 13110312032341 |
11 | 41a50633a2377 |
12 | 1578a48b819b1 |
13 | 7413b2a06a34 |
14 | 3347848315ad |
15 | 17b068d68711 |
hex | bec7b7dd855 |
13110312032341 has 8 divisors (see below), whose sum is σ = 13156956055904. Its totient is φ = 13063670247600.
The previous prime is 13110312032297. The next prime is 13110312032351. The reversal of 13110312032341 is 14323021301131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13110312032341 - 213 = 13110312024149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110312032351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11645395 + ... + 12721471.
It is an arithmetic number, because the mean of its divisors is an integer number (1644619506988).
Almost surely, 213110312032341 is an apocalyptic number.
It is an amenable number.
13110312032341 is a deficient number, since it is larger than the sum of its proper divisors (46644023563).
13110312032341 is a wasteful number, since it uses less digits than its factorization.
13110312032341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1119411.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13110312032341 its reverse (14323021301131), we get a palindrome (27433333333472).
The spelling of 13110312032341 in words is "thirteen trillion, one hundred ten billion, three hundred twelve million, thirty-two thousand, three hundred forty-one".
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