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131103142433 is a prime number
BaseRepresentation
bin111101000011001011…
…0110011001000100001
3110112101210200200112222
41322012112303020201
54121444401024213
6140121123200425
712320600216024
oct1720626631041
9415353620488
10131103142433
115066734039a
12214aa216115
13c4945b5933
1464b9bc51bb
153624b1a808
hex1e865b3221

131103142433 has 2 divisors, whose sum is σ = 131103142434. Its totient is φ = 131103142432.

The previous prime is 131103142409. The next prime is 131103142447. The reversal of 131103142433 is 334241301131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121136714209 + 9966428224 = 348047^2 + 99832^2 .

It is a cyclic number.

It is not a de Polignac number, because 131103142433 - 26 = 131103142369 is a prime.

It is not a weakly prime, because it can be changed into another prime (131103142403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551571216 + 65551571217.

It is an arithmetic number, because the mean of its divisors is an integer number (65551571217).

Almost surely, 2131103142433 is an apocalyptic number.

It is an amenable number.

131103142433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131103142433 is an equidigital number, since it uses as much as digits as its factorization.

131103142433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 131103142433 its reverse (334241301131), we get a palindrome (465344443564).

The spelling of 131103142433 in words is "one hundred thirty-one billion, one hundred three million, one hundred forty-two thousand, four hundred thirty-three".