Base | Representation |
---|---|
bin | 10011000100111111100… |
… | …110111101110001000001 |
3 | 11122100000002101111112101 |
4 | 103010333212331301001 |
5 | 132434443221014403 |
6 | 2442140242030401 |
7 | 163501412603434 |
oct | 23047746756101 |
9 | 4570002344471 |
10 | 1311032204353 |
11 | 466007556653 |
12 | 192106048401 |
13 | 968258b9201 |
14 | 4765083d81b |
15 | 2418272671d |
hex | 1313f9bdc41 |
1311032204353 has 2 divisors, whose sum is σ = 1311032204354. Its totient is φ = 1311032204352.
The previous prime is 1311032204351. The next prime is 1311032204441. The reversal of 1311032204353 is 3534022301131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1026193312144 + 284838892209 = 1013012^2 + 533703^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311032204353 - 21 = 1311032204351 is a prime.
Together with 1311032204351, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1311032204351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655516102176 + 655516102177.
It is an arithmetic number, because the mean of its divisors is an integer number (655516102177).
Almost surely, 21311032204353 is an apocalyptic number.
It is an amenable number.
1311032204353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311032204353 is an equidigital number, since it uses as much as digits as its factorization.
1311032204353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 1311032204353 its reverse (3534022301131), we get a palindrome (4845054505484).
The spelling of 1311032204353 in words is "one trillion, three hundred eleven billion, thirty-two million, two hundred four thousand, three hundred fifty-three".
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