Base | Representation |
---|---|
bin | 1011111011000111110000… |
… | …0111000011101110100011 |
3 | 1201102100000220120202101110 |
4 | 2332301330013003232203 |
5 | 3204244420014144301 |
6 | 43514444324434403 |
7 | 2522122003546005 |
oct | 276617407035643 |
9 | 51370026522343 |
10 | 13110322412451 |
11 | 41a5069242080 |
12 | 1578a50548a03 |
13 | 7413b4bcc604 |
14 | 334785d74375 |
15 | 17b069c190d6 |
hex | bec7c1c3ba3 |
13110322412451 has 16 divisors (see below), whose sum is σ = 19070003870208. Its totient is φ = 7945464948000.
The previous prime is 13110322412437. The next prime is 13110322412471. The reversal of 13110322412451 is 15421422301131.
It is not a de Polignac number, because 13110322412451 - 217 = 13110322281379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13110322412471) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3179416 + ... + 6027381.
It is an arithmetic number, because the mean of its divisors is an integer number (1191875241888).
Almost surely, 213110322412451 is an apocalyptic number.
13110322412451 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13110322412451 is a deficient number, since it is larger than the sum of its proper divisors (5959681457757).
13110322412451 is a wasteful number, since it uses less digits than its factorization.
13110322412451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9249962.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 13110322412451 its reverse (15421422301131), we get a palindrome (28531744713582).
The spelling of 13110322412451 in words is "thirteen trillion, one hundred ten billion, three hundred twenty-two million, four hundred twelve thousand, four hundred fifty-one".
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