Base | Representation |
---|---|
bin | 1011111011000111110000… |
… | …1110010100000101001100 |
3 | 1201102100001001011101102122 |
4 | 2332301330032110011030 |
5 | 3204244421011030234 |
6 | 43514444433312112 |
7 | 2522122025660120 |
oct | 276617416240514 |
9 | 51370031141378 |
10 | 13110324314444 |
11 | 41a506a321075 |
12 | 1578a51105638 |
13 | 7413b5417256 |
14 | 33478630b580 |
15 | 17b069e9292e |
hex | bec7c39414c |
13110324314444 has 48 divisors (see below), whose sum is σ = 27361517976576. Its totient is φ = 5374253438400.
The previous prime is 13110324314389. The next prime is 13110324314459. The reversal of 13110324314444 is 44441342301131.
13110324314444 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21871409 + ... + 22462839.
It is an arithmetic number, because the mean of its divisors is an integer number (570031624512).
Almost surely, 213110324314444 is an apocalyptic number.
13110324314444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13110324314444 is an abundant number, since it is smaller than the sum of its proper divisors (14251193662132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110324314444 is a wasteful number, since it uses less digits than its factorization.
13110324314444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625886 (or 625884 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 13110324314444 its reverse (44441342301131), we get a palindrome (57551666615575).
The spelling of 13110324314444 in words is "thirteen trillion, one hundred ten billion, three hundred twenty-four million, three hundred fourteen thousand, four hundred forty-four".
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