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131103300134155 = 531845827742801
BaseRepresentation
bin11101110011110011011101…
…101000100010010100001011
3122012012100112101212020111111
4131303303131220202110023
5114140444024313243110
61142500005152511151
736420620665130416
oct3563633550422413
9565170471766444
10131103300134155
1138856663084918
1212854845b4b4b7
13581ccacc8b85b
14245360da78b7d
15102546eb26e8a
hex773cdda2250b

131103300134155 has 8 divisors (see below), whose sum is σ = 162398926617984. Its totient is φ = 101499329136000.

The previous prime is 131103300134143. The next prime is 131103300134171. The reversal of 131103300134155 is 551431003301131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131103300134155 - 241 = 128904276878603 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 422913871246 + ... + 422913871555.

It is an arithmetic number, because the mean of its divisors is an integer number (20299865827248).

Almost surely, 2131103300134155 is an apocalyptic number.

131103300134155 is a deficient number, since it is larger than the sum of its proper divisors (31295626483829).

131103300134155 is an equidigital number, since it uses as much as digits as its factorization.

131103300134155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 845827742837.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 131103300134155 its reverse (551431003301131), we get a palindrome (682534303435286).

The spelling of 131103300134155 in words is "one hundred thirty-one trillion, one hundred three billion, three hundred million, one hundred thirty-four thousand, one hundred fifty-five".

Divisors: 1 5 31 155 845827742801 4229138714005 26220660026831 131103300134155