131103312020053 has 2 divisors, whose sum is σ = 131103312020054. Its totient is φ = 131103312020052.

The previous prime is 131103312019993. The next prime is 131103312020123. The reversal of 131103312020053 is 350020213301131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130960169351089 + 143142668964 = 11443783^2 + 378342^2 .

It is an emirp because it is prime and its reverse (350020213301131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131103312020053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131103312023053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551656010026 + 65551656010027.

It is an arithmetic number, because the mean of its divisors is an integer number (65551656010027).

Almost surely, 2^{131103312020053} is an apocalyptic number.

It is an amenable number.

131103312020053 is a deficient number, since it is larger than the sum of its proper divisors (1).

131103312020053 is an equidigital number, since it uses as much as digits as its factorization.

131103312020053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 131103312020053 its reverse (350020213301131), we get a palindrome (481123525321184).

The spelling of 131103312020053 in words is "one hundred thirty-one trillion, one hundred three billion, three hundred twelve million, twenty thousand, fifty-three".