13110332131 has 4 divisors (see below), whose sum is σ = 14118819232. Its totient is φ = 12101845032.

The previous prime is 13110332107. The next prime is 13110332197. The reversal of 13110332131 is 13123301131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13123301131 = 47 ⋅279219173.

It is a cyclic number.

It is not a de Polignac number, because 13110332131 - 2⁵ = 13110332099 is a prime.

It is a super-2 number, since 2×13110332131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110332099 and 13110332108.

It is not an unprimeable number, because it can be changed into a prime (13110332531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504243531 + ... + 504243556.

It is an arithmetic number, because the mean of its divisors is an integer number (3529704808).

Almost surely, 2^13110332131 is an apocalyptic number.

13110332131 is a deficient number, since it is larger than the sum of its proper divisors (1008487101).

13110332131 is a wasteful number, since it uses less digits than its factorization.

13110332131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008487100.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13110332131 its reverse (13123301131), we get a palindrome (26233633262).

The spelling of 13110332131 in words is "thirteen billion, one hundred ten million, three hundred thirty-two thousand, one hundred thirty-one".