Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1100001011100110101 |
3 | 110112101211001022210111 |
4 | 1322012113201130311 |
5 | 4121444423112044 |
6 | 140121131223021 |
7 | 12320601636106 |
oct | 1720627413465 |
9 | 415354038714 |
10 | 131103332149 |
11 | 5066745a989 |
12 | 214aa2a7a71 |
13 | c4946510aa |
14 | 64b9c343ad |
15 | 3624b56b34 |
hex | 1e865e1735 |
131103332149 has 2 divisors, whose sum is σ = 131103332150. Its totient is φ = 131103332148.
The previous prime is 131103332089. The next prime is 131103332159. The reversal of 131103332149 is 941233301131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77623532100 + 53479800049 = 278610^2 + 231257^2 .
It is an emirp because it is prime and its reverse (941233301131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131103332149 - 29 = 131103331637 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131103332149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131103332159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551666074 + 65551666075.
It is an arithmetic number, because the mean of its divisors is an integer number (65551666075).
Almost surely, 2131103332149 is an apocalyptic number.
It is an amenable number.
131103332149 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103332149 is an equidigital number, since it uses as much as digits as its factorization.
131103332149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 131103332149 in words is "one hundred thirty-one billion, one hundred three million, three hundred thirty-two thousand, one hundred forty-nine".
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