13110340210441 has 4 divisors (see below), whose sum is σ = 13130729542672. Its totient is φ = 13089950878212.

The previous prime is 13110340210417. The next prime is 13110340210469. The reversal of 13110340210441 is 14401204301131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110340210441 - 2¹¹ = 13110340208393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110340213441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10194665151 + ... + 10194666436.

It is an arithmetic number, because the mean of its divisors is an integer number (3282682385668).

Almost surely, 2^{13110340210441} is an apocalyptic number.

It is an amenable number.

13110340210441 is a deficient number, since it is larger than the sum of its proper divisors (20389332231).

13110340210441 is an equidigital number, since it uses as much as digits as its factorization.

13110340210441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20389332230.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13110340210441 its reverse (14401204301131), we get a palindrome (27511544511572).

The spelling of 13110340210441 in words is "thirteen trillion, one hundred ten billion, three hundred forty million, two hundred ten thousand, four hundred forty-one".