13110341400223 has 4 divisors (see below), whose sum is σ = 13110352444528. Its totient is φ = 13110330355920.

The previous prime is 13110341400139. The next prime is 13110341400329. The reversal of 13110341400223 is 32200414301131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13110341400223 - 2²¹ = 13110339303071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110341100223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3493011 + ... + 6198532.

It is an arithmetic number, because the mean of its divisors is an integer number (3277588111132).

Almost surely, 2^{13110341400223} is an apocalyptic number.

13110341400223 is a deficient number, since it is larger than the sum of its proper divisors (11044305).

13110341400223 is an equidigital number, since it uses as much as digits as its factorization.

13110341400223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11044304.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13110341400223 its reverse (32200414301131), we get a palindrome (45310755701354).

The spelling of 13110341400223 in words is "thirteen trillion, one hundred ten billion, three hundred forty-one million, four hundred thousand, two hundred twenty-three".