Base | Representation |
---|---|
bin | 1011111011000111110101… |
… | …0001111001111011010111 |
3 | 1201102100002021111120212120 |
4 | 2332301331101321323113 |
5 | 3204244440030024421 |
6 | 43514450305151023 |
7 | 2522122332405051 |
oct | 276617521717327 |
9 | 51370067446776 |
10 | 13110342033111 |
11 | 41a50793233a4 |
12 | 1578a5702b473 |
13 | 7413b8cac17b |
14 | 3347888008d1 |
15 | 17b06b7e28c6 |
hex | bec7d479ed7 |
13110342033111 has 16 divisors (see below), whose sum is σ = 18902520681984. Its totient is φ = 8051073620864.
The previous prime is 13110342033109. The next prime is 13110342033149. The reversal of 13110342033111 is 11133024301131.
It is a cyclic number.
It is not a de Polignac number, because 13110342033111 - 21 = 13110342033109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110342033511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2734737285 + ... + 2734742078.
It is an arithmetic number, because the mean of its divisors is an integer number (1181407542624).
Almost surely, 213110342033111 is an apocalyptic number.
13110342033111 is a deficient number, since it is larger than the sum of its proper divisors (5792178648873).
13110342033111 is a wasteful number, since it uses less digits than its factorization.
13110342033111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5469479430.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13110342033111 its reverse (11133024301131), we get a palindrome (24243366334242).
The spelling of 13110342033111 in words is "thirteen trillion, one hundred ten billion, three hundred forty-two million, thirty-three thousand, one hundred eleven".
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