Base | Representation |
---|---|
bin | 10011000100111111101… |
… | …111010101110101101011 |
3 | 11122100000020112001112121 |
4 | 103010333233111311223 |
5 | 132434444301300412 |
6 | 2442140401052111 |
7 | 163501440350155 |
oct | 23047757256553 |
9 | 4570006461477 |
10 | 1311034400107 |
11 | 466008816323 |
12 | 192106927037 |
13 | 968261a7783 |
14 | 47650c51ad5 |
15 | 24182a0c107 |
hex | 1313fbd5d6b |
1311034400107 has 2 divisors, whose sum is σ = 1311034400108. Its totient is φ = 1311034400106.
The previous prime is 1311034400077. The next prime is 1311034400161. The reversal of 1311034400107 is 7010044301131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311034400107 is a prime.
It is a super-2 number, since 2×13110344001072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311034400167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655517200053 + 655517200054.
It is an arithmetic number, because the mean of its divisors is an integer number (655517200054).
Almost surely, 21311034400107 is an apocalyptic number.
1311034400107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311034400107 is an equidigital number, since it uses as much as digits as its factorization.
1311034400107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1311034400107 its reverse (7010044301131), we get a palindrome (8321078701238).
The spelling of 1311034400107 in words is "one trillion, three hundred eleven billion, thirty-four million, four hundred thousand, one hundred seven".
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