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131103445023142 = 2325063201658517
BaseRepresentation
bin11101110011110011100110…
…010001001111100110100110
3122012012100220111111100211021
4131303303212101033212212
5114140444323411220032
61142500031410201354
736420624404512324
oct3563634621174646
9565170814440737
10131103445023142
1138856727946089
121285488658325a
135820003cbb297
142453624dd2d14
15102547c6e7097
hex773ce644f9a6

131103445023142 has 8 divisors (see below), whose sum is σ = 196655773485456. Its totient is φ = 65551520527992.

The previous prime is 131103445023119. The next prime is 131103445023163. The reversal of 131103445023142 is 241320544301131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1311034450231422 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131103445023098 and 131103445023107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100179133 + ... + 101479384.

It is an arithmetic number, because the mean of its divisors is an integer number (24581971685682).

Almost surely, 2131103445023142 is an apocalyptic number.

131103445023142 is a deficient number, since it is larger than the sum of its proper divisors (65552328462314).

131103445023142 is a wasteful number, since it uses less digits than its factorization.

131103445023142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201983582.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 131103445023142 its reverse (241320544301131), we get a palindrome (372423989324273).

The spelling of 131103445023142 in words is "one hundred thirty-one trillion, one hundred three billion, four hundred forty-five million, twenty-three thousand, one hundred forty-two".

Divisors: 1 2 325063 650126 201658517 403317034 65551722511571 131103445023142