Base | Representation |
---|---|
bin | 1011111011000111111000… |
… | …0100111100111000000011 |
3 | 1201102100010012200102201201 |
4 | 2332301332010330320003 |
5 | 3204300001441231111 |
6 | 43514451504042031 |
7 | 2522122554216664 |
oct | 276617604747003 |
9 | 51370105612651 |
10 | 13110355414531 |
11 | 41a5085933021 |
12 | 1578a5b603317 |
13 | 7413bb9b5b7b |
14 | 33478a4c536b |
15 | 17b06ca876c1 |
hex | bec7e13ce03 |
13110355414531 has 2 divisors, whose sum is σ = 13110355414532. Its totient is φ = 13110355414530.
The previous prime is 13110355414517. The next prime is 13110355414537. The reversal of 13110355414531 is 13541455301131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13110355414531 - 225 = 13110321860099 is a prime.
It is a super-2 number, since 2×131103554145312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13110355414537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555177707265 + 6555177707266.
It is an arithmetic number, because the mean of its divisors is an integer number (6555177707266).
Almost surely, 213110355414531 is an apocalyptic number.
13110355414531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110355414531 is an equidigital number, since it uses as much as digits as its factorization.
13110355414531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 13110355414531 in words is "thirteen trillion, one hundred ten billion, three hundred fifty-five million, four hundred fourteen thousand, five hundred thirty-one".
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