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13110401158207 is a prime number
BaseRepresentation
bin1011111011001000000011…
…0011011100110000111111
31201102100020101202110020221
42332302000303130300333
53204300100144030312
643514500220322211
72522123651066323
oct276620063346077
951370211673227
1013110401158207
1141a50a9736a11
121578a729a3367
137413c8310b32
143347925d1983
1517b071ac1207
hexbec80cdcc3f

13110401158207 has 2 divisors, whose sum is σ = 13110401158208. Its totient is φ = 13110401158206.

The previous prime is 13110401158123. The next prime is 13110401158271. The reversal of 13110401158207 is 70285110401131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13110401158207 - 211 = 13110401156159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110401158297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555200579103 + 6555200579104.

It is an arithmetic number, because the mean of its divisors is an integer number (6555200579104).

Almost surely, 213110401158207 is an apocalyptic number.

13110401158207 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110401158207 is an equidigital number, since it uses as much as digits as its factorization.

13110401158207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 34.

Adding to 13110401158207 its reverse (70285110401131), we get a palindrome (83395511559338).

The spelling of 13110401158207 in words is "thirteen trillion, one hundred ten billion, four hundred one million, one hundred fifty-eight thousand, two hundred seven".