Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0011011100110000111111 |
3 | 1201102100020101202110020221 |
4 | 2332302000303130300333 |
5 | 3204300100144030312 |
6 | 43514500220322211 |
7 | 2522123651066323 |
oct | 276620063346077 |
9 | 51370211673227 |
10 | 13110401158207 |
11 | 41a50a9736a11 |
12 | 1578a729a3367 |
13 | 7413c8310b32 |
14 | 3347925d1983 |
15 | 17b071ac1207 |
hex | bec80cdcc3f |
13110401158207 has 2 divisors, whose sum is σ = 13110401158208. Its totient is φ = 13110401158206.
The previous prime is 13110401158123. The next prime is 13110401158271. The reversal of 13110401158207 is 70285110401131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13110401158207 - 211 = 13110401156159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110401158297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555200579103 + 6555200579104.
It is an arithmetic number, because the mean of its divisors is an integer number (6555200579104).
Almost surely, 213110401158207 is an apocalyptic number.
13110401158207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110401158207 is an equidigital number, since it uses as much as digits as its factorization.
13110401158207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 34.
Adding to 13110401158207 its reverse (70285110401131), we get a palindrome (83395511559338).
The spelling of 13110401158207 in words is "thirteen trillion, one hundred ten billion, four hundred one million, one hundred fifty-eight thousand, two hundred seven".
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