1311040131 has 4 divisors (see below), whose sum is σ = 1748053512. Its totient is φ = 874026752.

The previous prime is 1311040117. The next prime is 1311040141. The reversal of 1311040131 is 1310401131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311040131 - 2⁵ = 1311040099 is a prime.

It is a super-2 number, since 2×1311040131² = 3437652450184994322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311040131.

It is not an unprimeable number, because it can be changed into a prime (1311040111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218506686 + ... + 218506691.

It is an arithmetic number, because the mean of its divisors is an integer number (437013378).

Almost surely, 2^1311040131 is an apocalyptic number.

1311040131 is a deficient number, since it is larger than the sum of its proper divisors (437013381).

1311040131 is an equidigital number, since it uses as much as digits as its factorization.

1311040131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437013380.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 1311040131 is about 36208.2881534049. The cubic root of 1311040131 is about 1094.4736963270.

Adding to 1311040131 its reverse (1310401131), we get a palindrome (2621441262).

The spelling of 1311040131 in words is "one billion, three hundred eleven million, forty thousand, one hundred thirty-one".