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13110401534003 is a prime number
BaseRepresentation
bin1011111011001000000011…
…0100111000100000110011
31201102100020102110112202022
42332302000310320200303
53204300100243042003
643514500232342055
72522123654223044
oct276620064704063
951370212415668
1013110401534003
1141a50a9973294
121578a72b4492b
137413c8412bb7
1433479268c8cb
1517b071b47738
hexbec80d38833

13110401534003 has 2 divisors, whose sum is σ = 13110401534004. Its totient is φ = 13110401534002.

The previous prime is 13110401533939. The next prime is 13110401534047. The reversal of 13110401534003 is 30043510401131.

It is a strong prime.

It is an emirp because it is prime and its reverse (30043510401131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13110401534003 - 26 = 13110401533939 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110401533003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555200767001 + 6555200767002.

It is an arithmetic number, because the mean of its divisors is an integer number (6555200767002).

Almost surely, 213110401534003 is an apocalyptic number.

13110401534003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110401534003 is an equidigital number, since it uses as much as digits as its factorization.

13110401534003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13110401534003 its reverse (30043510401131), we get a palindrome (43153911935134).

The spelling of 13110401534003 in words is "thirteen trillion, one hundred ten billion, four hundred one million, five hundred thirty-four thousand, three".