13110402043447 has 2 divisors, whose sum is σ = 13110402043448. Its totient is φ = 13110402043446.

The previous prime is 13110402043399. The next prime is 13110402043483. The reversal of 13110402043447 is 74434020401131.

It is a strong prime.

It is an emirp because it is prime and its reverse (74434020401131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110402043447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110402043747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201021723 + 6555201021724.

It is an arithmetic number, because the mean of its divisors is an integer number (6555201021724).

Almost surely, 2^{13110402043447} is an apocalyptic number.

13110402043447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110402043447 is an equidigital number, since it uses as much as digits as its factorization.

13110402043447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 34.

Adding to 13110402043447 its reverse (74434020401131), we get a palindrome (87544422444578).

The spelling of 13110402043447 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-three thousand, four hundred forty-seven".